已知i为虚数单位,计算|(1-i)^2/i|是多少

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|(1-i)^2/i|
=l（1-2i+1）/il
=l(2-2i)/il
=l-2i-2 l
=2+2i如果本题有什么不明白可以追问,
======以下答案可供参考======
供参考答案1:
|(1-i)^2/i|
=|1-i|^/|i|
=2.供参考答案2:
|(1-i)^2/i|
=|1-2i-1|/|i| //: |i| = 1
=|-2i|
=2|-i| //: |-i| = 1
=2