已知x=1/x,求（x²-5/x-1+1）乘以x³-1/x²-2x除以

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x=1/x则x=±1
（x²-5/x-1+1）乘以x³-1/x²-2x除以（x+3）
=(x²-5/x)X(x³-1/x²-2x)÷(x+3)
=[(x^3-5)/x]X[(x^5-1-2x^3)/x^2]÷(x+3)
=(x^3-5)(x^5-2x^3-1)/[x^3(x+3)]
当x=1时=(1-5)(1-2-1)/(1+3)
=(-4)(-2)/4
=2当x=-1时
=(-1-5)(-1+2-1)/(-1)(-1+3)
=(-4)(0)/(-2)
=0