解下列方程.??
①2X+20=110
②46X-38X=496
③15X÷2=60④8X+5.8=9.8⑤5X-12=60⑥1.6x-0.3x=3.9.
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解:(1)2X+20=110,
????? 2X+20-20=110-20,
??????????? 2x=90,
???????? 2x÷2=90÷2,
???????????? x=45;
(2)46X-38X=496,
????????? 8x=496,
?????? 8x÷8=496÷8,
?????????? x=62;
(3)15X÷2=60,
?? 15X÷2.2=60×2,
??????? 15x=120,
??? 15x÷15=120÷15,
????????? x=8;
(4)8X+5.8=9.8,
?8X+5.8-5.8=9.8-5.8,
???????? 8x=4,
????? 8x÷8=4÷8,
????????? x=0.5;
(5)5X-12=60,
? 5X-12+12=60+12,
??????? 5x=72,
???? 5x÷5=72÷5,
???????? x=14.4;
(6)1.6x-0.3x=3.9,
????????? 1.3x=3.9,
???? 1.3x÷1.3=3.9÷1.3,
???????????? x=3.
解析分析:(1)依据等式的性质,方程两边同时减20,再同时除以2求解,(2)先化简方程,再依据等式的性质,方程两边同时除以8求解,(3)依据等式的性质,方程两边同时乘2,再同时除以15求解,(4)依据等式的性质,方程两边同时减5.8,再同时除以8求解,(5)依据等式的性质,方程两边同时加12,再同时除以5求解,(6)先化简方程,再依据等式的性质,方程两边同时除以1.3求解.
点评:本题主要考查学生依据等式的性质解方程的能力,解答时注意:(1)方程能化简的先化简、(2)对齐等号.