Solve for x in terms of m2m(1 + x^2)-(1 +m^2)(x + m) = 0:
网友回答
由2m(1+x²)-(1+m²)(x+m)=0
2m+2mx²-x-m-m²x-m³=0
(2mx²-m²x-m³)-(x-m)=0
(2mx+m²)(x-m)-(x-m)=0(前面用十字相乘法)
(x-m)(2mx+m²-1)=0
∴x1=m, x2=(1-m²)/2m.
======以下答案可供参考======
供参考答案1:
2m+2mx^2-(x+m^2x+m+m^3)=0
mx^2-m^3+m-x=0
m(x+m)(x-m)-(x-m)=0
(x-m)(mx+m^2-1)=0
解得x=m或 x=(1/m)-m