若a满足不等式组{2(a-1)小于等于3a+1 a/3小于等于(a+1)/4 那么,代数式a^2-6*(a-1/a)/(1-1/a)最大值是多少代数式a^2-6*(a-1/a)/(1-1/a)的化简
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=a^2-6*{(a^2-1)/a}*{a/(a-1)}
=a^2-6*{(a-1)*(a+1)/a}*{a/(a-1)}
=a^2-6*(a+1)
=a^2-6a-6
=(a-3)^2-15
======以下答案可供参考======
供参考答案1:
=a^2-6*{(a^2-1)/a}*{a/(a-1)}
=a^2-6*{(a-1)*(a+1)/a}*{a/(a-1)}
=a^2-6*(a+1)
=a^2-6a-6
=(a-3)^2-15