已知a+b+c=0,求:a(1/b+1/c )+b(1/c+1/a)+c(1/a+1/b)的值

网友回答

因为a+b+c=0
所以 a+b=-c；a+c=-b；b+c=-a
a(1/b+1/c )+b(1/c+1/a)+c(1/a+1/b)
=a/b + a/c + b/c +b/a + c/a + c/b
=(b+c)/a + (a+c)/b + (a+b)/c
=-a/a + (-b/b) + (-c/c)
=-1-1-1
=-3======以下答案可供参考======
供参考答案1:
-3供参考答案2:
好难