①1÷2.5+2.5×0.4+1??????????????????????②×[-(-0.125)]③(×3.625+4.375×0.6)×1.25????????

发布时间:2020-08-06 21:30:20

①1÷2.5+2.5×0.4+1??????????????????????
②×[-(-0.125)]
③(×3.625+4.375×0.6)×1.25????????????
④1999÷(1999+)+.

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解:①1÷2.5+2.5×0.4+1
=0.4+1+1,
=2.4;

②×[-(-0.125)]
=×[-(-)],
=×[-(-)],
=×[-],
=×,
=;

③(×3.625+4.375×0.6)×1.25
=(0.6×3.625+4.375×0.6)×1.25
=(3.625+4.375)×0.6×1.25,
=8×1.25×0.6,
=10×0.6,
=6;

④1999÷(1999+)+
=1999÷1999+,
=1999÷+,
=1999×+,
=+,
=.
解析分析:算式①②根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式③可根据乘法分配律及乘法交换律时行计算;
算式④可根据乘法分配律及约分进行简算.

点评:完成算式④时要细心分析式中数据,注意通分约分.
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