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如图.在四棱锥P-ABCD中.底面ABCD是正方形.PD⊥底面ABCD.E为侧棱PD的中点
如图.在四棱锥P-ABCD中.底面ABCD是正方形.PD⊥底面ABCD.E为侧棱PD的中点
发布时间:2021-02-20 13:45:21
如图,在四棱锥P-ABCD中,底面ABCD是正方形,PD⊥底面ABCD,E为侧棱PD的中点,AC与BD的交点为O.求证:(1)直线OE∥平面PBC;(2)平面ACE⊥平面PBD.
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答案:
分析:
(1)利用三角形的中位线性质可得OE∥PB,再根据直线和平面平行的判定定理证得OE∥平面PBC.
(2)证明PD⊥AC,BD⊥AC,再根据直线和平面垂直的判定定理证得AC⊥平面PBD,再根据平面和平面垂直的判定定理证得平面ACE⊥平面PBD.
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如图.在四棱锥S-ABCD中.底面ABCD是正方形.四个侧面都是等边三角形.AC与BD的交
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