3×(8×7)×125???????????101×99?????????????37+37×3932×25????????????????201×42-42????

发布时间:2020-07-30 10:17:42

3×(8×7)×125???????????101×99?????????????37+37×3932×25????????????????201×42-42?????????????199+199×99.

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解:3×(8×7)×125,
=(3×7)×(8×125),
=21×1000,
=21000;

101×99,
=(100+1)×99,
=100×99+99,
=9900+99,
=9999;

37+37×39,
=37×(39+1),
=37×40,
=1480;

32×25,
=8×(4×25),
=8×100,
=800;

201×42-42,
=(201-1)×42,
=200×42,
=8400;

?199+199×99,
=199×(99+1),
=199×100,
=19900.
解析分析:3×(8×7)×125,利用乘法的交换律和结合律进行简算;32×25转化为8×4×25,然后利用乘法结合律进行简算;其它题都是利用乘法分配律进行简算.

点评:此题主要考查乘法交换律、结合律、分配律的实际应用.
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