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解答题已知a-b=2,a-c=1,求(2a-b-c)2+(c-a)2的值.
解答题已知a-b=2,a-c=1,求(2a-b-c)2+(c-a)2的值.
发布时间:2020-07-26 17:40:48
解答题已知a-b=2,a-c=1,求(2a-b-c)2+(c-a)2的值.
网友回答
解:(2a-b-c)2+(c-a)2,
=[(a-b)+(a-c)]2+(a-c)2,
当a-b=2,a-c=1时,原式=(2+1)2+12=9+1=10.解析分析:把(2a-b-c)整理成(a-b)+(a-c)的形式,然后整体代入数据进行计算即可得解.点评:本题考查了代数式求值,把所求代数式整理成已知条件的形式是解题的关键.
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