产物,反应进行10min后,反应物反应掉30%.求该反应的k和t(下脚标)1/2

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一级反应 ln[Ca,0/Ca]=kt,则ln[Ca,0/0.7Ca,0]==kt
kt=0.3567 k=0.03567/min
t1/2==ln2/k ===0.693/0.03567=19.43min
======以下答案可供参考======
供参考答案1:
k=1/tln(C1/C1-x)=1/t ln[1/(1－α)]=0.0357min-1
t1/2=ln2/k=19.4min