如图,C是线段AB上一点,D是线段BC上一点,E是线段AD的中点,如果AB=10cm,AC=6cm,EC=五分之一AD,则线段BD的长为————cm（结果精确到0.01cm）图画得不好,请见谅
网友回答
EC=1/5 x AD
E是线段AD的中点,则AE = 1/2 x AD
AC = AE+EC = (1/5 + 1/2)AD = 7/10 X AD = 6CM
AD = 6X 10/7 = 8.57CM
BD = AB-AD = 10-8.57 = 1.43CM
很高兴为你解答,希望能够帮助到你.基础教育团队祝你学习进步!
不理解就追问,理解了请采纳!
======以下答案可供参考======
供参考答案1:
AC = AE + EC = (1/2 + 1/5) AD = 6
7/10 AD = 6
AD = 60/7
BD = AB - AD = 10 - 60/7 = 10/7 = 1.43厘米