a²(a²+b²)(a²-b²)+(a²+b²)(2a四次方-3b的四次方)
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a²(a²+b²)(a²-b²)+(a²+b²)(2a^4-3b^4)
=(a²+b²)[a²(a²-b²)+(2a^4-3b^4)]
=(a²+b²)[a^4-a²b²+2a^4-3b^4]
=(a²+b²)(3a^4-a²b²-3b^4)
======以下答案可供参考======
供参考答案1:
a²(a²+b²)(a²-b²)+(a²+b²)(2a四次方-3b的四次方)
=(a²+b²)[a²(a²-b²)+2a^4-3b^4]
=(a²+b²)[3a^4-a²b²-3b^4]