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如图.在四棱锥S-ABCD中.∠ADB=90°.AD=BD=1.SA⊥平面ABCD.∠AS
如图.在四棱锥S-ABCD中.∠ADB=90°.AD=BD=1.SA⊥平面ABCD.∠AS
发布时间:2021-02-22 09:47:02
如图,在四棱锥S-ABCD中,∠ADB=90°,AD=BD=1,SA⊥平面ABCD,∠ASB=30°,E、F分别是SD、SC上的动点,M、N分别是SB、SC上的动点,且SESD=SFSC=λ,SMSB=SNSC=μ.
(I)当λ,μ有何关系时,ME⊥平面SAD?并证明你的结论;
(II)在(I)的条件下且μ=12时,求三棱锥S-AME的体积.
网友回答
答案:
分析:
(I)λ=μ通过比例关系
SE
SD
=
SF
SC
=λ
SM
SB
=
SN
SC
=μ
λ=μ
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