（x-1分之x + x-1分之1）除以x^2-2x+1分之x+1其中x=-2
网友回答
答：[x/(x-1)+1/(x-1)]÷[(x+1)/(x²-2x+1)]
=[(x+1)/(x-1)]÷[(x+1)/(x-1)²]
=[(x+1)/(x-1)]×[(x-1)²/(x+1)]
=x-1======以下答案可供参考======
供参考答案1:
[x/(x-1) +1/( x-1)]/[(x+1)/(x²-2x+1)]
=[(x+1)/(x-1)]/[(x+1)/(x-1)²]
=[(x+1)/(x-1)]*(x-1)²/(x+1)
=x-1供参考答案2:
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