初中内容解下列方程:(1)6(3x-2)-4(4x-3)=1-8x;(2)4(x-2)+20x-4=5(1-2x);(3)x÷(144÷9)=0.0625;(4)1.

发布时间:2020-07-30 21:09:18

初中内容解下列方程:
(1)6(3x-2)-4(4x-3)=1-8x;
(2)4(x-2)+20x-4=5(1-2x);
(3)x÷(144÷9)=0.0625;
(4)1.6÷(x-0.45)=5;
(5)35(x-2)-15(5x-6)=(22x-63)-21(3x-4).

网友回答

解;(1)6(3x-2)-4(4x-3)=1-8x,
??????????? 18x-12-16x+12=1-8x,
?????????????? 18x-16x+8x=0,
????????????????????? 10x=1,
??????????????????????? x=1÷10,
??????????????????????? x=;

(2)4(x-2)+20x-4=5(1-2x),
?????? 4x-8+20x-4=5-10x,
??????????24x+10x=5+12,
????????????? 34x=17,
??????????????? x=17÷34,
????????????????x=;

(3)x÷(144÷9)=0.0625,
???????????? x÷16=0.0625,
???????????????? x=0.0625×16,
???????????????? x=1;

(4)1.6÷(x-0.45)=5,
??????????? x-0.45=1.6÷5,
????????????x-0.45=0.32,
???????????????? x=0.32+0.45,
???????????????? x=0.77;

(5)35(x-2)-15(5x-6)=(22x-63)-21(3x-4),
??????????35x-70-75x+90=22x-63-63x+84,
-40x+20=-41x+21,
-40x+41x=21-20,
????????????????????? x=1.

解析分析:根据等式的基本性质解答.

点评:解决本题主要依据等式的基本性质.在计算过程中要注意等号对齐.
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