递等式计算.
(1)7000÷25-28×6(2)(289-179)÷(275÷25)(3)++(4)--(5)+-(6)-+(7)+-(8)-+.
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解:(1)7000÷25-28×6,
=280-168,
=112;
(2)(289-179)÷(275÷25),
=110÷11,
=10;
(3)++,
=+,
=,
=;
(4)--,
=-,
=;
(5)+-,
=-,
=,
=;
(6)-+,
=+,
=;
(7)+-,
=1-,
=;
(8)-+,
=+-,
=-,
=,
=.
解析分析:(1)先算乘法和除法,再算减法;
(2)先算两个小括号里面的减法和除法,再算括号外的除法;
(3)(4)(5)(6)(7)按照从左到右的顺序计算;
(8)运用加法交换律进行计算.
点评:本题考查了简单的混合运算,计算时先理清楚运算顺序,根据运算顺序逐步求解即可.