递等式计算(能简算的要写出简算过程)1.25×2.5×32[2-(0.5+×2.4)]÷10÷8+3.96×12.5%+2.04×.

发布时间:2020-07-31 08:05:59

递等式计算(能简算的要写出简算过程) 1.25×2.5×32[2-(0.5+×2.4)]÷10÷8+3.96×12.5%+2.04×.

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解:(1)1.25×2.5×32,
=1.25×2.5×8×4,
=(1.25×8)×(2.5×4),
=10×10,
=100;

(2)[2-(0.5+×2.4)]÷,
=[2-(0.5+1)]÷,
=[2-1.5]×20,
=0.5×20,
=10;

(3)7-(4.5×+2)÷5,
=7.5-(1+2)÷5,
=7-3÷,
=-,
=;

(4)10÷8+3.96×12.5%+2.04×,
=1.25+3.96×0.125+2.04×0.125,
=1.25+(3.96+2.04)×0.125,
=1.25+6×0.125,
=1.25+0.75,
=2.

解析分析:(1)可将32拆分为8×4后根据乘法交换律及结合律计算;(2)(3)根据四则混合运算的运算顺序计算即可,先算乘除,再算加减,有括号的要先算括号里面的;(4)可将12.5%与变为统一的数据形式后根据乘法分配律计算.

点评:当算式中同时含有中括号与小括号时,要先算小括号里面的,再算中括号里面的.
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