1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a]log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log(1/2)[a]=log(1/2) [
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a=(1/2)^(ln2)
a*b>1b/(2^ln2)>1因为ln2>02^ln2>1>0b>2^ln2>1alog(a)b