【分解因式：(x+2)(x+4)+x^2-4 （x^2意思是x的2次方）】

网友回答

(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x+2)(x-2)
=(x+2)(x+4+x-2)
=(x+2)(2x+2)
=2(x+2)(x+1)
提示：运用提取公因式法
======以下答案可供参考======
供参考答案1:
(x+2)(x+4)+x^2-4
=x^2+6x+8+x^2-4
=2x^2+6x+4
=2(x^2+3x+2)
=2(x+2)(x+1)
供参考答案2:
(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x^2-2^2)
=(x+2)(x+4)+(x+2)(x-2)
=(x+2)(x+4+x-2)
=(x+2)(2x+2)
=2(x+1)(x+2).
供参考答案3:
=2(x^2+3x+2)
=2(x+1)(x+2)
供参考答案4:
(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x+2)(x-2)
=(x+2)(x+4+x-2)
=(x+2)(2x+2)
=2(x+2)(x+1)
供参考答案5:
(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x+2)(x-2)
=(x+2)(x+4+x-2)
=(x+2)(2x+2)
=2(x+2)(x+1)
供参考答案6:(x+2)(x+4)+x^2-4
=x^2+6x+8+x^2-4
=2x^2+6x+4
=2(x+2)(x+1)