x+1分之x的平方-6x+9除以x的平方+x分之x的平方-9
网友回答
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)
=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]
=x(x-3)/(x+3)
x的平方=4 x=2或x=-2
原式=-2/5或10
======以下答案可供参考======
供参考答案1:
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)
=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]
=x(x-3)/(x+3)