计算2i-[(3+2i)-(-1+3i)]

网友回答

原式=2i-[3+2i+1-3i]
=2i-[4-i]
=3i-4======以下答案可供参考======
供参考答案1:
2i-[(3+2i)-(-1+3i)]
=2i-(4-i)
=-4+3i
供参考答案2:
2i-[(3+2i)-(-1+3i)]
=2i-(3+2i+1-3i)
=2i-(4-i)
=2i-4+i
=3i-4