(1)若两等差数列{an},{bn}的前n项和分别为An,Bn,满足An/Bn=(7n+1)/(4n

发布时间:2021-02-20 11:28:15

(1)若两等差数列{an},{bn}的前n项和分别为An,Bn,满足An/Bn=(7n+1)/(4n+27),则a11/b11的值为( )(2)已知等比数列{an},首项为81,数列{bn}满足bn=log3(an),其前n项和为Sn.①证明{bn}为等差数列;②若S11≠S12,且S11最大,求{bn}的公差d的范围.

网友回答

1,S21=(a1+a21)*21/2a1+a21=a1+a1+20d=2(a1+10d)=2a11所以S21=2a11*21/2=21*a11同理T21=21*b11所以a11/b11=S21/T21=(7*21+1)/(4*21+27)=4/3 2,(1)等比数列{an},首项为81设an=a1*q^(n-1)=81*q^(n-1)数列{bn}满足bn=l...
======以下答案可供参考======
供参考答案1:
1a11/b11
=2a11/2b11
=(a1+a21)/(b1+b21)
=[21*(a1+a21)/2]/[21*(b1+b21)/2]
=A21/B21=(7*21+1)/(4*21+27)=148/111
2(1)bn-b(n-1)
=log3 an-log3 a(n-1)
=log3 [an/a(n-1)]
设等比数列公比为q
则bn-b(n-1)=log3 q为定值
∴{bn}为等差数列
(2)b1=log3 a1=4
S12=S11+a12
∵S11最大,且S11≠S12
∴a12<0
即4+11d<0
d<-4/11
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