解方程.(1)x-30%=9????????????????????????????(2)20%x÷=100(3)0.75x+125%x=4?????????????

发布时间:2020-07-30 20:55:58

解方程.
(1)x-30%=9????????????????????????????
(2)20%x÷=100
(3)0.75x+125%x=4?????????????????????
(4)(12.5+12.5%)×4=5x.

网友回答

解:(1)x-30%=9,
???????? x-0.3=9,
???? x-0.3+0.3=9+0.3,
???????????? x=9.3;

(2)20%x÷=100,
????? 0.2x÷=100,
? 0.2x÷×=100×,
?????????0.2x=20,
??? 0.2x÷0.2=20÷0.2,
??????????? x=100;

(3)0.75x+125%x=4,
???? 0.75x+1.25x=4,
? (0.75+1.25)x=4,
????????????? 2x=4,
?????????? 2x÷2=4÷2,
?????????????? x=2;

(4)(12.5+12.5%)×4=5x,
???? (12.5+1.25)×4=5x,
?????????????????? 55=5x,
??????????????? 5x÷5=55÷5,
??????????????????? x=11.
解析分析:(1)原式变为x-0.3=9,根据等式的性质,两边同加上0.3即可;(2)原式变为 0.2x÷=100,根据等式的性质,两边同乘,得0.2x=20,两边再同除以0.2即可;(3)原式变为0.75x+1.25x=4,根据乘法分配律改写成(0.75+1.25)x=4,即2x=4,再根据等式的性质,两边同除以2即可;(4)原式变为(12.5+1.25)×4=5x,即55=5x,根据等式的性质,两边同除以5即可.

点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
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