（x分之x-1-x+1分之x-2）除以x^2+2X+1分之2x^2-X ,其中满足x^2-X-1=0 需要过程

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[(x-1)/x - (x-2)/(x+1)] ÷ (2x²-x)/(x²+2x+1)=[(x+1)(x-1)-x(x-2)]/x(x+1) × (x²+2x+1)/x(2x-1)=(x²-1-x²+2x)/x(x+1) × (x+1)²/x(2x-1)=(2x-1)/x × (x+1)/x(2x-1)= (x+1)/x²因为x²-x-1=0所以原式=(x+1)/x²=x²/x²=1