试题难度:难度:中档 试题类型:填空题 试题内容:由金红石(TiO2)制取单质Ti,涉及到的步骤为:TiO2→TiCl4镁/800℃/ArTi已知:①C(s)+O2(g)=CO2(g);△H=-393.5kJ•mol-1②2CO(g)+O2(g)=2CO2(g);△H=-566kJ•mol-1③TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g);△H=+141kJ•mol-1,则TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)的△H=______kJ/mol.
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试题答案:根据盖斯定律①×2-②+③得TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)△H=(-393.5kJ•mol-1)×2-(-566kJ•mol-1)+(+141kJ•mol-1),即TiO2(s)+2Cl2(g)+2C(s)=TiCl4(s)+2CO(g)△H=-80kJ/mol,故答案为:-80.