因式分解m^2-1-4n^2+4n

网友回答

m^2-1-4n^2+4n
=m^2-(4n^2-4n+1)
=m^2-(2n-1)^2
=(m+2n-1)(m-2n+1)
======以下答案可供参考======
供参考答案1:
m^2-1-4n^2+4n
=m^2-(4n^2-4n+1)
=m^2-(2n-1)^2
=(m+2n-1)(m-2n+1)
供参考答案2:
m^2-1-4n^2+4n
=m^2-(4n^2-4n+1)=m^2-(2n-1）^2=(m+2n-1)(m-2n+1)供参考答案3:
m²-（4n²-4n+1）
=m²-（2n-1）²
=（m+2n-10(m-2n+1)
供参考答案4:
m²-1-4n²+4n
=m²-（4n²-4n+1）
= m²-（2n-1）²
=（m+2n-1）（m-2n+1）
供参考答案5:
m^2-(4n^2-4n+1)
=m^2-(2n-1)^2
做到这里应该看出来答案了吧。 a^2-b^2=(a+b)(a-b)