x减二分之x减一=2-三分之x+2 怎么算
网友回答
x减二分之x减一=2-三分之x+2
x/2 -1=2-(x+2)/3
3x -6=12-2(x+2)
3x -6=12-2x-4
5x=14x=14/5
======以下答案可供参考======
供参考答案1:
x减二分之x减一=2-三分之x+2
x/2 -1=2-(x+2)/3
3x -6=12-2(x+2)
3x -6=12-2x-4
5x=14x=14/5
供参考答案2:
x - (x - 1)/2 = 2 - (x+2)/3
两边同乘以 6 得
6x - 3(x - 1) = 12 - 2(x + 2)
6x - 3x + 3 = 12 - 2x - 4
5x = 5x = 1