(1)(-x-y)(x-y)+(x+y)2;(2)(2a6x3-9ax6)÷(3ax3);(3)(2x-5)(2x+5)-(2x+1)(2x-3);(4);(5)-2

发布时间:2020-08-07 06:49:16

(1)(-x-y)(x-y)+(x+y)2;
(2)(2a6x3-9ax6)÷(3ax3);
(3)(2x-5)(2x+5)-(2x+1)(2x-3);
(4);
(5)-23+8-1×(-1)3×(-)-2+7°;
(6)(2x-y+1)(2x+y-1);
(7);
(8)(a+2)(a2+4)(a4+16)(a-2);
(9)(x-y)2(x2+y2)2(x+y)2;
(10)(5m3n2)2?(-2m2)3?(-n3)4;
(11)(π-3)0+(-0.125)2009×82009;
(12)(2am-3bn)(3an+5bm);
(13)(x+y)(x-y)-(x-y)2;
(14)(-2a2+3a)-(a2-2a+1);
(15)-2a(a2b+a-1)
(16)[x4y-2x2(x2-3xy2)]÷(-2x3)
(17)(2m+n)(3n+1)
(18)1012
(19)199×201
(20)20082
(21)782
(22)(a+b+1)(a+b-1)
(23)(a-b)(a+b)(a2+b2)
(24)(66x6y3-24x4y2+9x2y)÷(-3x2y).

网友回答

解:(1)(-x-y)(x-y)+(x+y)2;
=-x2+y2+x2+2xy+y2,
=2y(y+x);
(2)(2a6x3-9ax6)÷(3ax3);
=;
(3)(2x-5)(2x+5)-(2x+1)(2x-3);
=4x2-25-4x2+4x+3,
=4x-22;
(4);
=a4b5;
(5)-23+8-1×(-1)3×(-)-2+7°;
=-8+,
=-8-,
=-7;
(6)(2x-y+1)(2x+y-1);
=4x2-4xy+y2-1;
(7);
=8y-1;
(8)(a+2)(a2+4)(a4+16)(a-2);
=a8-256;
(9)(x-y)2(x2+y2)2(x+y)2;
=x8-2x4y4+y8;
(10)(5m3n2)2?(-2m2)3?(-n3)4;
=25m6n4?(-8m6)?n12
=-200m12n16,
(11)(π-3)0+(-0.125)2009×82009;
=1+(-1)
=0;
(12)(2am-3bn)(3an+5bm);
=6am+n+10ambm-9anbn-15bm+n;
(13)(x+y)(x-y)-(x-y)2;
=-+xy,
=-y2+xy;
(14)(-2a2+3a)-(a2-2a+1);
=-3a2+5a-1;
(15)-2a(a2b+a-1),
=-2a3b-2a2+2a;
(16)[x4y-2x2(x2-3xy2)]÷(-2x3)
=-+x-3y2;
(17)(2m+n)(3n+1)
=6mn+2m+3n2+n;
(18)1012
=(100+1)2
=10000+200+1,
=10201;
(19)199×201
=(200-1)(200+1)
=40000-1,
=39999;
(20)20082
=(2000+8)2
=4000000+32000+64,
=4032064;
(21)782
=(80-2)2
=6400-320+4,
=6084;
(22)(a+b+1)(a+b-1)
=(a+b)2-1,
=a2+2ab+b2-1,
(23)(a-b)(a+b)(a2+b2),
=a4-b4;
(24)(66x6y3-24x4y2+9x2y)÷(-3x2y).
=-22x4y2+8x2y-3.
解析分析:本题需先根据整式的混合运算顺序和法则以及乘法公式,分别进行计算,即可求出结果.

点评:本题主要考查了整式的混合运算,在解题时要根据整式的混合运算和法则分别进行计算是本题的关键.
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