已知:(1)Zn(s)+1/2O2(g)=ZnO(s);ΔH=-348.3kJ/mol(2)2Ag(s)+1/2O2(g)=Ag2O(s);Δ

发布时间:2020-08-04 08:31:22

已知:(1)Zn(s)+1/2O2(g)=ZnO(s);ΔH=-348.3kJ/mol(2)2Ag(s)+1/2 O2(g)= Ag2O(s);ΔH= -31.0kJ/mol则Zn(s)+ Ag2O(s)= ZnO(s)+ 2Ag(s)的ΔH等于A.-317.3kJ/molB.-379.3kJ/molC.-332.8 kJ/molD.+317.3 kJ/mol

网友回答

A解析考查反应热的计算。根据盖斯定律可知,(1)-(2)即得到Zn(s)+ Ag2O(s)= ZnO(s)+ 2Ag(s),所以该反应的ΔH=-348.3kJ/mol+31.0kJ/mol=-317.3kJ/mol,
以上问题属网友观点,不代表本站立场,仅供参考!