一道初一计算(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16

发布时间:2021-03-11 22:11:01

一道初一计算(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16

网友回答

(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)-2^16
=(2^4-1)(2^4+1)(2^8+1)-2^16
=2^16-2^16
=0
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