1.√41²-40²/196 2.2√1又2分之1除以41√6分之1 3.√20a除以三分之二√b乘以√a分之b
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√41²-40²/196
=√9²/196
=9/14
2.2√1又2分之1除以41√6分之1
=2√(3/2) / [41√(1/6)]
=2/41*√(3/2x6)
=2/41*√9
=6/41
3.√20a除以三分之二√b乘以√a分之b
=2√5a x √(b/a) x 3/(2√b)
=2√(5axb/a) x 3/2(√b)
=2√(5b) x 3/2(√b)
=3√5======以下答案可供参考======
供参考答案1:
1.√41²-40²/196
=√(41+40)(41-40)/196
=√81/196
=9/142.2√1又2分之1除以41√6分之1
=2√(3/2)÷41√(1/6)
=2/41 ×√(3×6/2)
=2/41×3
=6/413.√20a除以三分之二√b乘以√a分之b
=2√5a×3/(2√b)×√(b/a)
=3√5