定义一种新运算“*”：x*y=1/xy+1/（x+1）+1/y+A,已知2*1=4/3,求2005*

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x*y=1/xy+1/（x+1）+1/y+A,
2*1=4/3 = 1/2 + 1/3 + 1 + A,A = -1/2
2005*2006
= 1/(2005*2006) + 1/2006 + 1/2006 -1/2
= 1/2005 + 1/2006 -1/2
= (2005+2006)/ (2*2005*2006)
= 1/2 (1/2006+1/2006)
======以下答案可供参考======
供参考答案1:
2*1=1/2+1/3+1/1+A=4/3 解得：A=-1/2
2005*2006=1/4022030+1/2006+1/2006-1/2=-1004502/20011015
供参考答案2:
2*1=1/2+1/3+1/(1+A)=4/3
1/(1+A)=4/3-1/2-1/3=1/2
1+A=2A=12005*2006
=1/2005×2006+1/2006+1/2007
=1/2005-1/2006+1/2006+1/2007
=1/2005-1/2007
=2/4024035