5^log5(2)-4^log2(3)+3^log27(8)等于多少?(1)5^log5(2) -

发布时间:2021-03-16 06:52:23

5^log5(2)-4^log2(3)+3^log27(8)等于多少?(1)5^log5(2) - 4^log2(3) + 3^log27(8)等于多少?(2)开更号[lg2 (1/3) - 4lg(3) + 4 + lg(6) - 2^(-1)]等于多少?

网友回答

5^log5(2) - 4^log2(3) + 3^log27(8)
=2 - 2^2log2(3) + 27^[(1/3)log27(8)]
=2 - 2^log2(9) + 27^[log27(2)]
=2 - 9 + 2
= -5
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