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某人投篮球3次.三次中能中一次的概率为54125.能中2次的概率为36125.能中3次的概
某人投篮球3次.三次中能中一次的概率为54125.能中2次的概率为36125.能中3次的概
发布时间:2021-02-22 09:19:56
某人投篮球3次,三次中能中一次的概率为54125,能中2次的概率为36125,能中3次的概率为8125,那么此人三次投篮都不中的概率为( )
A.54125
B.27125
C.8125
D.36125
网友回答
答案:
分析:
根据题意,易得“投篮命中”与“三次投篮都不中”为对立事件,而“投篮命中”有3种情况,即“投中1次”、“投中2次”、“投中3次”,依题意,易得“投篮命中”的概率,由对立事件的概率性质,可得答案.
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