问一道关于对数的计算题目a=2 b=3

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======以下答案可供参考======
供参考答案1:
答：①式中等号右边的log(2) 2^(1/4)/(a+2)=log(2) 2^(1/4) - log(2) (a+2)
=1/4+log(1/2) (a+2)
所以消去log(1/2) (a+2)，得1/(a+2)=1/4，所以a=2。
②式同理，b=3.
不是很理解的话可以代值：log(2) (8) =3，log(1/2) (8)=-3，所以log(a) (b)=-log(1/a) (b)
供参考答案2:
对数符号不好打,以下log均表示以2为底.
1/(a+2)-log(a+2)=log[2^(1/4)/(a+2)]
1/(a+2)-log(a+2)=log[2^(1/4)]-log(a+2)
1/(a+2)=log[2^(1/4)]
1/(a+2)=(1/4)*log2=1/4
a+2=4a=21/(b+2)-log(b+2)=log[2^(1/5)/(b+2)]
1/(b+2)-log(b+2)=log[2^(1/5)]-log(b+2)
1/(b+2)=log[2^(1/5)]
1/(b+2)=(1/5)*log2=1/5
b+2=5b=3