在标准状况下,700lnh3全部溶解在1l水中,如果该氨水的密度为0.85g·cm,则nh3的物质的量浓度为?
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n(NH3)=700L/22.4L/mol=31.25mol
m(NH3)=17g/mol×31.25mol=531.25g
m(H2O)=ρ(H2O)V(H2O)=1g/cm3×1000cm3=1000g
m氨水=531.25g+1000g=1531.25g
V氨水=m氨水/ρ氨水=1531.25g/0.85g/cm3=1801.47mL=1.8L
c(NH3)=31.25mol/1.8L=17.36mol/L