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写出a1=1,an=an+1-1/a数列的前五项,急,要有过程
写出a1=1,an=an+1-1/a数列的前五项,急,要有过程
发布时间:2021-03-05 06:36:50
写出a1=1,an=an+1-1/a数列的前五项,急,要有过程
网友回答
an=an+1-1/a
所以an+1=an+1/a
每一项都等于前一项+1/a
a1=1a2=1+1/a
a3=1+2/a
a4=1+3/a
a5=1+4/a
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an,a与one的区别
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在数列{an}的第一项a1=1,又a(n+1)=(2/an)+1,求这个数列的第五项
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