java,求救!利用随机函数生成矩阵;对角线求和;每行最小数及位置

发布时间:2021-03-16 09:42:11

java,求救!利用随机函数生成矩阵;对角线求和;每行最小数及位置

网友回答

import java.util.ArrayList;
import java.util.List;
import java.util.Random;
public class Matrix {
private int i;
private int j;
private List rows;
public Matrix(int i,int j){
this.i = i;
this.j = j;
rows = new ArrayList();
for(int r = 0; r List tempList = new ArrayList();
for(int c = 0; c int temp = new Random().nextInt(100);
tempList.add(temp);
}this.rows.add(tempList);
}}public void show(){
for(int r = 0; r List row = (List)rows.get(r);
System.out.print('[');
int c = 0;
for(;c System.out.print( row.get(c) + \t);
}System.out.println(row.get(c) + ]);
}}public int diagonal(){
if(i == j){
int result = 0;
for(int r = 0; r result += rows.get(r).get(r);
}return result;
}else{
return -1;
}}public int getMin(int rr){
int r = rr - 1;List row = rows.get(r);int min = row.get(0);for(int c = 0; c if(row.get(c) min = row.get(c);}}return min;}public String getPos(int rr){int r = rr - 1;return + rr + , + (rows.get(r).indexOf(getMin(rr)) + 1);}}public class Test {/*** @param args*/public static void main(String[] args) {Matrix m = new Matrix(5,7);//5行7列m.show();//显示矩阵System.out.println(m.getMin(1));//第1行最小值System.out.println(m.getPos(1));//第一行最小值位置}}[55 60 63 15 74 56 50][6
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