数学计算题:(log6三)^2+log6十八*log6二=?郁闷,6是底数,三/十八/二是真数.过程写清楚些,元旦快乐~闷死,刚才都问两遍了
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(log6三)^2+log6十八*log6二 =(log6三)^2+（log6三+log6六）*log6二 =(log6三)^2+log6三*log6二+log6二 =log6三（log6三+log6二）+log6二 =log6三+log6二 =1
======以下答案可供参考======
供参考答案1:
=(log6 3)^2+(log6 6+log6 3)+log6 2 =(log6 3)^2+log6 3log6 2 +log6 2 =log6 3(log6 3+log6 2)+log6 2 =log6 3+log6 2 =log6 6 =1