(-9m的2次+4n的2次)除以(3m+2n)

网友回答

(-9m^2+4n^2)÷(3m+2n)
=(4n^2-9m^2)÷(3m+2n)
=(2n+3m)(2n-3m)÷(3m+2n)
=2n-3m
======以下答案可供参考======
供参考答案1:
(-9m^2+4n^2)/(3m+2n)
=-(3m+2n)(3m-2n)/(3m+2n)
=2n-3m
供参考答案2:
(-9m^2+4n^2)/(3m+2n)
=-(3m+2n)(3m-2n)/(3m+2n)
=-(3m-2n)
=2n-3m