初二数学√12-√1/3+1/5√75= √24-√3/2+√2/3-√6= √3(3√6-√12+

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√12-√1/3+1/5√75
=2√3-√3/3+(1/5)×5√3
=2√3-√3/3+√3
=8√3/3;
√24-√3/2+√2/3-√6
=2√6-√6/2+√6/3-√6
=√6-√6/6
=5√6/6;
√3(3√6-√12+√1/3=
=√3(3√6-2√3+√3/3)
=9√2-6+1
=9√2-5;
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======以下答案可供参考======
供参考答案1:
√12-√1/3+1/5√75
=2√3-1/3√3+√3
=8/3(√3)
√24-√3/2+√2/3-√6
=2√6-1/2√6+1/3√6-√6
=5/6(√6)
√3(3√6-√12+√1/3)
=9√2-6+1
=-5+9√2