已知立方根下x-3和立方根下3-2y互为相反数,求x+y分之3x-2y的值

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已知立方根下x-3和立方根下3-2y互为相反数,
所以x-3=2y-3;
x=2y;求x+y分之3x-2y的值
=(6y-2y)/(2y+y)
=(4y)/(3y)
=4/3;很高兴为您解答,skyhunter002为您答疑解惑
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======以下答案可供参考======
供参考答案1:
³√(x-3)与³√(3-2y)互为相反数，则有
³√(x-3)+³√(3-2y)=0 且(x-3)与(3-2y)也是互为相反数
(x-3)+(3-2y)=0
x-2y=0
x=2y所以 (3x-2y)/(x+y)
=(3*2y-2y)/(2y+y)
=4y/3y
=4/3