质量相等、边长分别为a、b、c、(a

网友回答

m(a-h)/(a^3)=m(b-h)/(b^3)
(a-h)b^3=(b-h)a^3
h=(a(b^3)-(a^3)b)/(b^3-a^3)
=a-(b-a)(a^3)/(b^3-a^3)
=a-(a^3)/(b^2+ab+a^2)
=a-(a^3)/((b+a/2)^2+3(a^2)/4)
令f(x)=a-(a^3)/((x+a/2)^2+3(a^2)/4)
则h=f(b),h'=f(c),易得x>0时,f(x)递增
所以c>b时,f(c)>f(b),即h'>hA选项写错了吧?