有一个3*3的整型二维数组,写一个函数,当主函数调用此函数后,能求出平均值、最大值和最小值.如题,是

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#include <iostream>
using namespace std;
void num_calc(int array[3][3],double & aver_num,int & max_num,int & min_num);
int main()
{int a[3][3] = { 1,2,3,
7,8,9,
4,5,6 };
int max_num,min_num;
double aver_num;
num_calc(a,aver_num,max_num,min_num);
// print the number,you also can use printf with library stdio.h included.
cout << The average number is: << aver_num << endl;
cout << The max number is: << max_num << endl;
cout << The min number is: << min_num << endl;
}void aver_calc(int array[3][3],double & aver_num)
{int sum = 0;
for(int i = 0; i < 3; i++)
for(int j = 0; j < 3; j++)
{sum += array[i][j];
}aver_num = sum / 9.0;
}void max_calc(int array[3][3],int & max_num)
{max_num = array[0][0];
for(int i = 0; i < 3; i++)
for(int j = 0; j < 3; j++)
{if(max_num < array[i][j])
max_num = array[i][j];
}}void min_calc(int array[3][3],int & min_num)
{min_num = array[0][0];
for(int i = 0; i < 3; i++)
for(int j = 0; j < 3; j++)
{if(min_num > array[i][j])
min_num = array[i][j];
}}void num_calc(int array[3][3],double & aver_num,int & max_num,int & min_num)
{aver_calc(array,aver_num);
max_calc(array,max_num);
min_calc(array,min_num);
}