设集合M={1,2,3,4,5},集合N={2,4,6},集合T={4,5,6},则(M∩T)∪N是A.{2,4,5,6}B.{4,5,6}C.{1,2,3,4,5,6}D.{2,4,6}
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A
解析分析:已知集合M={1,2,3,4,5},集合N={2,4,6},集合T={4,5,6},根据交集的定义求出M∩T,再根据并集的定义求出(M∩T)∪N;
解答:∵集合M={1,2,3,4,5},集合T={4,5,6},
M∩T={4,5},∵集合N={2,4,6},
∴(M∩T)∪N={2,4,5,6},
故选A;
点评:此题主要考查交集和并集的定义,注意有括号先算括号里面的,此题是一道基础题;