已知4^m=8,16^n=6,求4^(2m-4n+1)的值
网友回答
4^(2m-4n+1)
=(4^2m)/(4^4n)*4
=4*(4^m)^2/(16^n)^2
=4*8^2/6^2
=64/9======以下答案可供参考======
供参考答案1:
4^(2m-4n+1)
=4^(2m)/4^(4n)*4
=(4^m)^2/(16^n)^2*4
=8^2/6^2*4
=64/9供参考答案2:
4^(2m-4n+1)
=(4^2m)÷(4^4n)×4
=4×(4^m)^2÷(16^n)^2
=4×8^2÷6^2
=64/9