只有一道题而已!关于分式加减的计算!

网友回答

[1+(2/(x-2)]^2+[1-2/(x-2)]^2=x/(x-2)
1+4/(x-2)+4/(x-2)^2+1-4/(x-2)+4/(x-2)^2=x/(x-2)
2+8/(x-2)^2=x/(x-2)
2(x-2)^2+8-x(x-2)=0
2x^2-8x+16-x^2+2x=0
x^2-6x+16=0
△＝36－4×16＝－28