求未知数x的值
(1)4.8÷120%x=40?????????????????
(2)x+4.8=5.
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解:(1)4.8÷120%x=40,
??4.8÷120%x×120%x=40×120%x,
??????????????? 4.8=48x,
????????????4.8÷48=48x÷48,
??????????????????x=0.1;
???????????
(2)x+4.8=5,
?x+4.8-4.8=5-4.8,
???????? x=0.2,
????? x=0.2,
?????????? x=.
解析分析:(1)依据等式的性质,方程两边同时同时乘120%x,再同时除以48求解,(2)依据等式的性质,方程两边同时减4.8,再同时除以求解.
点评:本题主要考查学生依据等式的性质解方程的能力.