已知在发射卫星时可用肼(N2H4)为燃料和NO2作氧化剂，两者反应生成N2和水蒸气。又知：N2(g)＋2O2(g)===2NO2(g) ΔH＝＋67.7kJ·mol－1N2H4(g)＋O2(g)===N2(g)＋2H2O(g) ΔH＝－534kJ·mol－1则肼与NO2反应的热化学方程式为A.N2H4(g)＋NO2(g)===3/2N2(g)＋2H2O(g) ΔH＝＋567.85kJ·mol－1B.N2H4(g)＋NO2(g)===3/2N2(g)＋2H2O(g) ΔH＝－567.85kJ·mol－1C.N2H4(g)＋NO2(g)===3/2N2(g)＋2H2O(l) ΔH＝＋567.85kJ·mol－1D.N2H4(g)＋NO2(g)===3/2N2(g)＋2H2O(l) ΔH＝－567.85kJ·mol－1
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B解析根据盖斯定律可知，②－①÷2即得到N2H4(g)＋NO2(g)===3/2N2(g)＋2H2O(g)，所以该反应的反应热ΔH＝－534kJ·mol－1－67.7kJ·mol－1÷2＝－567.85kJ·mol－1，